Question: Dimensions of frequency are: [PMT/NEET-1988]
a. $M^{0} L^{-1} T^{0}$
b. $M^{0} L^{0} T^{-1}$
c. $M^{0} L T$
d. $M T^{-2}$

Solution

Frequency ($\nu$) is defined as:
$
\nu = \frac{1}{\text{Time Period }(T)}
$

Time period has the dimension:
$
[T] = T
$

Therefore, frequency has the dimension:
$
[\nu] = T^{-1}
$

No dependence on mass ($M$) or length ($L$).

$
[\nu] = M^{0} L^{0} T^{-1}
$

Answer:
b. $M^{0} L^{0} T^{-1}$