Question: Dimensions of kinetic energy are: [PMT/NEET-1991]
a. $ML^{2}T^{-2}$
b. $M^{2}LT^{-1}$
c. $ML^{2}T^{-1}$
d. $MLT^{-1}$
Solution
Kinetic energy $E_k = \tfrac{1}{2}mv^{2}$.
$
= M \times (LT^{-1})^{2} = ML^{2}T^{-2}
$
Answer
a. $ML^{2}T^{-2}$
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Updated on September 12, 2025
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