If the error in the measurement of radius of a sphere is 2%, then the error in the determination of volume of the sphere will be: [PMT/NEET-2008]

a. 8%
b. 2%
c. 4%
d. 6%

Answer: d. 6%

Solution:
Volume of sphere

$$ V=\dfrac{4}{3}\pi R^{3} $$

Thus

$$ \dfrac{\Delta V}{V}=3\dfrac{\Delta R}{R}=3\times 2\%=6\% $$