Question: Unit of magnetic moment is: [PMT/NEET-1989]
a. Ampere–metre$^2$
b. Ampere–metre
c. Weber–metre$^2$
d. Weber/metre

Answer: a. Ampere–metre$^2$

Solution: Magnetic dipole moment

$M = \text{pole strength} \times \text{separation} = q_m \times 2l$.

In SI, $q_m$ corresponds via current loop:

$M=I\,A$ with unit $ \text{A m}^2$.